std: Do not allocate the result for ChildProcess.init

Instead, just return ChildProcess directly. This structure does not
require a stable address, so we can put it on the stack just fine. If
someone wants it on the heap they should do.

  const proc = try allocator.create(ChildProcess);
  proc.* = ChildProcess.init(args, allocator);

1 files changed, 1 insertions, 3 deletions

diff --git a/test/tests.zig b/test/tests.zig
index 5b15da2bcb..ee4b922021 100644
--- a/test/tests.zig
+++ b/test/tests.zig
@@ -731,9 +731,7 @@ pub const StackTracesContext = struct {
                 return ExecError.ExecNotSupported;
             }
 
-            const child = std.ChildProcess.init(args.items, b.allocator) catch unreachable;
-            defer child.deinit();
-
+            var child = std.ChildProcess.init(args.items, b.allocator);
             child.stdin_behavior = .Ignore;
             child.stdout_behavior = .Pipe;
             child.stderr_behavior = .Pipe;